MCQ
Let $A = \left[ {\begin{array}{*{20}{c}}5&{5\alpha }&\alpha \\0&\alpha &{5\alpha }\\0&0&5\end{array}} \right]$, If ${\left| A \right|^2} = 25$, then $\left| \alpha \right|$ equals
- ✓$\frac{1}{5}$
- B$5$
- C${5^2}$
- D$1$
$\Rightarrow(25 \alpha)^{2}=25 \Rightarrow|\alpha|=\frac{1}{5}$
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$(1,1)(-1,1),(1,-1),(-1,-1),(-2,1)(2,-1),(-1,2)$ and $(-2,-1)$