10x^9+10^x _e10 10^x+x^ 10 dx is equal to : - Vidyadip

MCQ

$\int\frac{10\text{x}^9+10^\text{x}\log_\text{e}10}{10^\text{x}+\text{x}^{10}}\text{dx}$ is equal to :

A
$10^\text{x}-\text{x}^{10}+\text{c}$
B
$10^\text{x}+\text{x}^{10}+\text{c}$
C
$(10^\text{x}-\text{x}^{10})^{-1}+\text{c}$
✓
$\log_\text{e}(10^\text{x}+\text{x}^{10}+\text{c}$

✓

Answer

Correct option: D.

$\log_\text{e}(10^\text{x}+\text{x}^{10}+\text{c}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Integrals→Integrals — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Let $\text{f(x)}=|\cos\text{x}|.$ Then,

If $\text{A}=\begin{bmatrix}\cos\theta&-\sin\theta\\\sin\theta&\cos\theta\end{bmatrix},$ then $A^T + A = I_2,$ if:

${d \over {dx}}\sqrt {{{1 + \cos 2x} \over {1 - \cos 2x}}} = $

If $f: R \rightarrow R$ is a function defined by $f(x)=[x-1] \cos \left(\frac{2 x-1}{2}\right) \pi,$ where $[.]$ denotes the greatest integer function, then $f$ is

$\int\limits^1_{-1}|1-\text{x}|\text{dx}$ is equal to:

The order and the degree of differential equation $\frac{{{d^4}y}}{{d{x^4}}} - 4\frac{{{d^3}y}}{{d{x^3}}} + 8\frac{{{d^2}y}}{{d{x^2}}} - 8\frac{{dy}}{{dx}} + 4y = 0$ are respectively

Area of the region bounded by the curves $y = sinx,\ y = x$ , between the lines $x = 0$ and $x = 2\pi $ , is

If $y = {{\sqrt {{x^2} + 1} + \sqrt {{x^2} - 1} } \over {\sqrt {{x^2} + 1} - \sqrt {{x^2} - 1} }}$, then ${{dy} \over {dx}} = $

If the given vectors $( - bc,\,{b^2} + bc,\,{c^2} + bc),$ $({a^2} + ac,\, - ac,\,{c^2} + ac)$ and $({a^2} + ab,\,{b^2} + ab,\, - ab)$ are coplanar, where none of $a, b $ and $ c $ is zero, then

$A$ is a $2 × 2$ matrix such that $A$ $\left[ {\begin{array}{*{20}{c}}1\\{ - 1} \end{array}} \right]$ $=$$\left[ {\begin{array}{*{20}{c}}{ - 1}\\2\end{array}} \right]$ and $A^2$ $\left[ {\begin{array}{*{20}{c}}1\\{ - 1}\end{array}} \right]$ $=$ $\left[ {\begin{array}{*{20}{c}}1\\0\end{array}} \right]$ . The sum of the elements of $A$, is