Maharashtra BoardEnglish MediumSTD 12 ScienceMathsDefinite Integration2 Marks
MCQ
$\int_3^4 \sqrt{\frac{x-3}{4-x}} d x=$
A
$0$
B
$\frac{\pi}{4}$
✓
$\frac{\pi}{2}$
D
$\pi$
✓
Answer
Correct option: C.
$\frac{\pi}{2}$
(C) Here, $a =3$ and $b =4$ $\int_{ a }^{ b } \sqrt{\frac{x- a }{ b -x}} d x=\frac{\pi}{2}(b- a )$ $\therefore \int_3^4 \sqrt{\frac{x-3}{4-x}} d x=\frac{\pi}{2}(4-3)=\frac{\pi}{2}$
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