MCQ
The proposition $(p \wedge q) \wedge(p \rightarrow\sim q$) is
- ✓Contradiction
- BTautology
- CContingency
- DTautology and Contradiction
| p | q | ∼q | $p \wedge q$ | $p \rightarrow \sim q$ | $( p \wedge q )\wedge( p \rightarrow \sim q )$ |
| T | T | F | T | F | F |
| T | F | T | F | T | F |
| F | T | F | F | T | F |
| F | F | T | F | T | F |
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$\text{X}:$
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$1$
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$2$
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$3$
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$4$
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$\text{P}(\text{X}):$
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$\frac{1}{10}$
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$\frac{1}{5}$
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$\frac{3}{10}$
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$\frac{2}{5}$
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