Question
Integrate the function $x^2 \log x$

Answer

$\int {{x^2}\log xdx} $$= \int {\left( {\log x} \right){x^2}dx} $
$= \log x\int {{x^2}dx - \int {\left( {\frac{d}{{dx}}\log x\int {{x^2}dx} } \right)dx} } $
[Applying product rule]
$= \left( {\log x} \right)\frac{{{x^3}}}{3} - \int {\frac{1}{x}.\frac{{{x^3}}}{3}dx} $
$= \frac{{{x^3}}}{3}\log x - \frac{1}{3}\int{x^2}dx$
$= \frac{{{x^3}}}{3}\log x - \frac{1}{3}\frac{{{x^3}}}{3} + c$
$= \frac{{{x^3}}}{3}\log x - \frac{{{x^3}}}{9} + c$

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