Question
Integrate with respect to $x$ :
$\frac{1-x^2}{1+x^2}$
$\frac{1-x^2}{1+x^2}$
✓
Answer
Let $I =\int \frac{1-x^2}{1+x^2} d x$
Here degree of numerator is same as that of denominator. So integration can be done by dividing the numerator by denominator.
$
\therefore I=\int \frac{1-x^2}{1+x^2} d x
$
Here degree of numerator is same as that of denominator. So integration can be done by dividing the numerator by denominator.
$
\therefore I=\int \frac{1-x^2}{1+x^2} d x
$
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