Download App

Differential Equations — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsDifferential Equations2 Marks
MCQ
Integrating factor of linear differential equation $x \frac{d y}{d x}+2 y=x^2 \log x$ is .....
  • A
    $\frac{1}{x^2}$
  • B
    $\frac{1}{x}$
  • C
    $x$
  • D
    $x^2$
✓

Answer

$\begin{aligned} & x^2 \\ & \frac{d y}{d x}+\frac{2 y}{x}=x \log x \\ & P=\frac{2}{x} \\ & \text { I. } F=e^{\int \frac{2}{x} d x}=e^{2 \log x}=x^2\end{aligned}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Differential Equations→Differential Equations — all question types→Maths STD 12 Science question papers→Maharashtra Board STD 12 Science question papers→Maharashtra Board question paper generator→

Similar questions

If the surrounding air is kept at 20°C and the body cools from 80°C to 70°C in 5 minutes, the temperature of the body after 15 minutes will be…..
→
If $(1,2,-3)$ is the foot of the perpendicular drawn from origin on a plane, then equation of that plane is
→
The equation of the plane containing the lines $\bar{r}=\hat{i}+2 \hat{j}-\hat{k}+\lambda(\hat{i}+2 \hat{j}-\hat{k})$ and $\bar{r}=\hat{i}+2 \hat{j}-\hat{k}+\mu(\hat{i}+\hat{j}+3 \hat{k})$ is
→
If $3\sin^{-1}\Big(\frac{2\text{x}}{1+\text{x}^2}\Big)-4\cos^{-1}\Big(\frac{1-\text{x}^2}{1+\text{x}^2}\Big)+2\tan^{-1}\Big(\frac{2\text{x}}{1-\text{x}^2}\Big)=\frac{\pi}{3}$ is equal to:
→
If $f(x)=\frac{x}{x^2+1}$ is increasing function, then the value of $x$ lies in
→
The general solution of $\sin x-\cos x=\sqrt{2}$, for any integer n is
→
If $\theta$ is the angle between two vectors $\vec{\text{a}}$ and $\vec{\text{b}},$ then $\vec{\text{a}}.\vec{\text{b}}\geq0$ only when:
→
If p.m.f. of a d.r.v. $\mathrm{X}$ is $\mathrm{P}(\mathrm{X}=\mathrm{x})=\frac{x}{n(n+1)}$, for $\mathrm{x}=1,2,3, \ldots \ldots, \mathrm{n}$ and $=0$, otherwise, then $\mathrm{E}(\mathrm{X})$ $=$
→
The approximate value of tan (44° 30′), given that 1° = 0.0175, is
→
If $\frac{ a }{ b } \tan x>-1$, then $\tan ^{-1}\left[\frac{ a \cos x- b \sin x}{b \cos x+ a \sin x}\right]$ is
→