_0^ , , x x ( 1 + x ) ^2 dx is equal to : - Vidyadip

MCQ

$\int\limits_0^\pi {\,\,\frac{{x\cos x}}{{{{\left( {1 + \sin x} \right)}^2}}}} dx$ is equal to :

A
$\pi -2$
B
$- (2 + \pi )$
C
zero
✓
$2 -\pi$

✓

Answer

Correct option: D.

$2 -\pi$

d
Take $x$ as the first and $\frac{{\cos \,\,x}}{{{{\left( {1\,\, + \,\,\sin \,x} \right)}^2}}}$ as the second function. $I B P$

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