MCQ
$\int\limits_0^\pi {} $ $(x · sin^2x · cos x) dx $ =
- A$0$
- B$2/9$
- C$- 2/9$
- ✓$- 4/9$
✓
Answer
Correct option: D.
$- 4/9$
d
$\int\limits_0^\pi {x\,\cdot\,({{\sin }^2}x\;\cos x)\,dx} $= $x\,\cdot\,\left. {\frac{{{{\sin }^3}x}}{3}} \right|_{\,0}^{\,\pi } - \int\limits_0^\pi {\frac{1}{3}{{\sin }^3}x\;dx} $
$\int\limits_0^\pi {x\,\cdot\,({{\sin }^2}x\;\cos x)\,dx} $= $x\,\cdot\,\left. {\frac{{{{\sin }^3}x}}{3}} \right|_{\,0}^{\,\pi } - \int\limits_0^\pi {\frac{1}{3}{{\sin }^3}x\;dx} $
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