MCQ
$\int_{\pi /4}^{3\pi /4} {\frac{\phi }{{1 + \sin \phi }}\,d\phi ,} $=
- ✓$\pi \tan \frac{\pi }{8}$
- B$\log \tan \frac{\pi }{8}$
- C$\tan \frac{\pi }{8}$
- Dએકપણ નહીં.
$\left\{ \because \frac{\pi }{4}+\frac{3\pi }{4}=\pi \right\}$
==> $2I = \int_{\pi /4}^{3\pi /4} {\frac{\pi }{{1 + \sin \phi }}d\phi } $
On simplification, we get
$I = \pi (\sqrt 2 - 1) = \pi \tan \frac{\pi }{8}.$
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