Question
$\int_{\pi /4}^{\pi /2} {\cos \theta \,{\rm{cose}}{{\rm{c}}^{\rm{2}}}\theta \,d\theta = } $
$t = \sin \theta $ रखने पर
$ \Rightarrow dt = \cos \theta \,\,d\theta $
$\int_{1/\sqrt 2 }^1 {\frac{1}{{{t^2}}}dt} = \left[ {\frac{{ - 1}}{t}} \right]_{1/\sqrt 2 }^1 $
$= \sqrt 2 - 1$.
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