Question
$\int_{}^{} {{{\left( {x + \frac{1}{x}} \right)}^3}} dx = $

Answer

b
(b) $\int_{}^{} {{{\left( {x + \frac{1}{x}} \right)}^3}dx = \int_{}^{} {\left( {{x^3} + \frac{1}{{{x^3}}} + 3x + \frac{3}{x}} \right)\,dx} } $
$ = \frac{{{x^4}}}{4} - \frac{1}{{2{x^2}}} + \frac{{3{x^2}}}{2} + 3\log x + c$
$ = \frac{{{x^4}}}{4} + \frac{{3{x^2}}}{2} + 3\log x - \frac{1}{{2{x^2}}} + c.$

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