MCQ
Iodine is formed when potassium iodide reacts with a solution of
- A$ZnS{O_4}$
- ✓$CuS{O_4}$
- C${(N{H_4})_2}S{O_4}$
- D$N{a_2}S{O_4}$
$2Cu{I_2}\, \to \,\mathop {2CuI\,\,\,\,\,\,\, + \,\,\,\,\,{I_2}}\limits_{{\rm{Cuprous iodide}}\,\,\,\,\,\,\,\,\,\,} $
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${K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ & ${CuSO}_4$
SideX $SPM$ Side $\mathrm{Y}$ Due to osmosis :
$B$ is green colored compound then it would be
$Me_2CHCH_2NHCH_2CH_2Me $ $\xrightarrow[\begin{smallmatrix}
(ii)\,A{{g}_{2}}O \\
(iii)\,\Delta
\end{smallmatrix}]{(i)\,C{{H}_{3}}-I(excess)}$ Product