MCQ
Iodine is released when potassium iodide reacts with
- A$ZnS{O_4}$
- ✓$CuS{O_4}$
- C$FeS{O_4}$
- D${(N{H_4})_2}S{O_4}$
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$\mathrm{X} \xrightarrow[Zn/H_2O]{O_3}\mathrm{A} \xrightarrow{[Ag(NH_3)_2]^+}$$\mathrm{B}(3-\text {oxo}-\text {hexane dicarboxylic acid})$
$X$ will be
