Ionisation constant of a weak acid (HA) in terms of _m^ and _m - Vidyadip

MCQ

Ionisation constant of a weak acid $(HA)$ in terms of $\Lambda _m^\infty $ and ${\Lambda _m}$

A
${K_a} = \frac{{C\Lambda _m^\infty }}{{\left( {{\Lambda _m} - {\Lambda ^\infty }} \right)}}$
✓
${K_a} = \frac{{C\Lambda _m^2}}{{\Lambda _m^\infty \left( {\Lambda _m^\infty - {\Lambda _m}} \right)}}$
C
${K_a} = \frac{{C{{\left( {\Lambda _m^\infty } \right)}^2}}}{{\Lambda _m^\infty \left( {\Lambda _m^\infty - {\Lambda _m}} \right)}}$
D
None of these

✓

Answer

Correct option: B.

${K_a} = \frac{{C\Lambda _m^2}}{{\Lambda _m^\infty \left( {\Lambda _m^\infty - {\Lambda _m}} \right)}}$

b
$\alpha = \frac{{{\Lambda _m}}}{{\Lambda _m^\infty }}$

${K_a} = \frac{{C{\alpha ^2}}}{{1 - \alpha }}$

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