MCQ
$\ce{IP}$ is influenced by :
- ASize of atom
- BEffective nuclear charge.
- CElectrons present in inner shell.
- ✓All
✓
Answer
Correct option: D.
All
$\ce{IP}$ is influenced by:
size of atom : Higher is the size of the atom, lower will be its ionization potential.
Effective nuclear charge : Higher is the effective nuclear charge, higher will be its ionisation potential.
Electrons present in inner shell : When more electrons are present in inner shells, higher is the screening effect and lower is the effective nuclear charge.
Hence, lower will be the ionization potential.
size of atom : Higher is the size of the atom, lower will be its ionization potential.
Effective nuclear charge : Higher is the effective nuclear charge, higher will be its ionisation potential.
Electrons present in inner shell : When more electrons are present in inner shells, higher is the screening effect and lower is the effective nuclear charge.
Hence, lower will be the ionization potential.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The hybridisation of $S$ in $SF_4$ is
→Here $,A$ refers to :
→Which of the following has $ds{p^2}$ hybridization
→In an adiabatic process, no transfer of heat takes place between system and surroundings. Choose the correct option for free expansion of an ideal gas under adiabatic condition from the following.
Concentration of $\ce{H_2O_2}$ by vacuum distillation gives hydrogen peroxide which is :
→The total internal energy change for a reversible isothermal cycles is
Two gaseous equilibrium $\mathrm{SO}_{2}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) \rightleftharpoons \mathrm{SO}_{3(\mathrm{g})}$ and $2 \mathrm{SO}_{3(\mathrm{g})} \rightleftharpoons 2 \mathrm{SO}_{2(\mathrm{g})}+\mathrm{O}_{2}(\mathrm{g})$ have equilibrium constant $K_1$ and $K_2$ respectively at $298\, K$. Which of the following relationship between $K_1$ and $K_2$ is correct ?
→The $pH$ of a buffer solution containing $25\,ml$ of $1\,M\,C{H_3}COONa$ and $25\,\,ml$ of $1\,\,M\,\,C{H_3}COOH$ will be appreciably affected by $5\,\,ml$ of
→Reaction, ${H_2}(g) + {I_2}(g) \to 2HI(g)$ $\Delta H = - 12.40\,kcal$. According to this, the heat of formation of $ HI $ will be......$kcal$
→The half $-$ cell reaction is the one that :
→