ઇરવીન શ્રેડિન્જર નામના વૈજ્ઞાનિકે સૌપ્રથમ તારવેલ ઇલેકટ્રોન કક્ષકીય તરંગવિધેયનું સમીકરણ ...... છે.

Question

A$\frac{{{d^2}\Psi }}{{d{x^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{y^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{z^2}}}\, + \,\frac{{8\pi m}}{{{h^2}}}\,(V\, - \,E)\,\Psi = 0$
B$\frac{{{d^2}\Psi }}{{d{x^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{y^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{z^2}}}\, + \,\frac{{8{\pi ^2}m}}{{{h^2}}}\,(E\, - \,V)\,\Psi \,\, = \,\,0$
C$\frac{{{d^2}\Psi }}{{d{x^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{y^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{z^2}}}\, + \,\frac{{8{\pi ^2}m}}{{{h^2}}}\,(V\, - \,E)\Psi \,\, = \,\,0$
D$\frac{{{d^2}\Psi }}{{d{x^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{y^2}}}\, + \,\frac{{{d^2}\Psi }}{{d{z^2}}}\, + \,\frac{{8{\pi ^2}m}}{h}\,(E\, - \,V)\Psi \, = \,0$

Medium

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Solution

b
(B) its obvious

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