Question
Is it possible to design a rectangular mango grove whose length is twice its breadth and the area is $800m^2$?
If so, find its length and breadth.
If so, find its length and breadth.
✓
Answer
Let the breadth of the rectangular mango grove be $x$ meter.
Given that length is twice that of breadth,
lengrh$ = 2 \times xm$
Given that area of the grove is $800m^2.$
But we know that
Area of a rectangle = length $\times$ breadth
$\Rightarrow 800m^2 = 2xm \times xm$
$\Rightarrow 2x^2 = 800$
$\Rightarrow x^2 = 400$
$\Rightarrow\text{x}=\sqrt{400}$
$\Rightarrow\text{x}=\sqrt{(20)^2}$
$\Rightarrow\text{x}\pm20$
Since, $x$ cannot be a negative value
So, $x = 20\ m$
Breadth of the manogo grove $= 20\ m$ and length of the mango grove
$= 2xm = 2 × 20\ m = 40\ m$
Yes. It is possible to dising a rectangular mango grove whose length is twice its breadth and the area is $800\ m^2$.
Given that length is twice that of breadth,
lengrh$ = 2 \times xm$
Given that area of the grove is $800m^2.$
But we know that
Area of a rectangle = length $\times$ breadth
$\Rightarrow 800m^2 = 2xm \times xm$
$\Rightarrow 2x^2 = 800$
$\Rightarrow x^2 = 400$
$\Rightarrow\text{x}=\sqrt{400}$
$\Rightarrow\text{x}=\sqrt{(20)^2}$
$\Rightarrow\text{x}\pm20$
Since, $x$ cannot be a negative value
So, $x = 20\ m$
Breadth of the manogo grove $= 20\ m$ and length of the mango grove
$= 2xm = 2 × 20\ m = 40\ m$
Yes. It is possible to dising a rectangular mango grove whose length is twice its breadth and the area is $800\ m^2$.
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