MCQ
$.....$ is the midpoint of $(1, 2)$ and $(5, 8):$
- A$(2, 5)$
- ✓$(3, 5)$
- C$(5, 2)$
- D$(5, 3)$
✓
Answer
Correct option: B.
$(3, 5)$
We know, midpoint of $(x_1, y_1)$ and $(x_2, y_2)$ is $\Big(\frac{{\text{x}}_{1}+{\text{x}}_{2}}{2}, \frac{{\text{y}}_{1}+{\text{y}}_{2}}{2}\Big)$
So, midpoint of $(1, 2)$ and $(5, 8)$ is $\Big(\frac{1+5}{2}, \frac{2+8}{2}\Big)$ is $(3, 5)$
So, midpoint of $(1, 2)$ and $(5, 8)$ is $\Big(\frac{1+5}{2}, \frac{2+8}{2}\Big)$ is $(3, 5)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Let $n$ be a positive integer such that $\sin \frac{\pi }{{{2^n}}} + \cos \frac{\pi }{{{2^n}}} = \frac{{\sqrt n }}{2}.$ Then
→For what value of $\theta, 1$ lies between the roots of the quadratic equation $3\text{x}^2 – 3\sin\theta \text{x} – 2\cos^2\theta = 0$
→If $\text{z}=1-\cos\theta+\text{i}\sin\theta,$ then $|\text{z}|=$
→For any two sets A and $\text{B, A - B}\cup\text{B}=\text{A}=$
→A card is drawn from a pack of $52$ cards. A gambler bets that it is a spade or an ace. What are the odds against his winning this bet
→For $k \in N$, let $\frac{1}{\alpha(\alpha+1)(\alpha+2) \ldots(\alpha+20)}=\sum_{k=0}^{20} \frac{A_{k}}{a+k}$, where $a\,>\,0$. Then the value of $100\left(\frac{A_{14}+A_{15}}{A_{13}}\right)^{2}$ is equal to $....$
→In what direction a line be drawn through the point $(1, 2)$ so that its points of intersection with the line $x + y = 4$ is at a distance $\frac{{\sqrt 6 }}{3}$ from the given point
→$\tan \frac{A}{2}$ is equal to
→If the graph of $y = ax^2 + bx + c$ $\left( {a,b,c \in R} \right)$ is as follows: $(D = b^2 - 4ac)$ which of the following is incorrect
→Let $a, b, x$ be positive real numbers with $a \neq 1$, $x \neq 1$, ab $\neq 1$. Suppose $\log _{ a } b =10$, and $\frac{\log _{ a } x \log _{ x }\left(\frac{ b }{ a }\right)}{\log _{ x } b \log _{ ab } x }=\frac{ p }{ q }$, where $p$ and $q$ are positive integers which are coprime. Then $p+q$ is
→