Question
Isomers of the compound $\ce{C4H9Br}$ are:
✓
Answer
$(c) 1-$Bromobutane$, 2 - $Bromobutane$, 1-$ bromo$-2-$methylpropane, and $2-$bromo$-2-$methylpropane
Explanation: Isomers are compounds having the same molecular formula but different structures. In the given straight$-$chain $4-C$ compounds$, Br$ is placed at different positions but the molecular formula is same.
In the given branched $4-C$ compounds, there is a branching of $-CH3$ at carbon $2$ but $Br$ is placed at positions $1$ and $2$ respectively.
So, all of these are isomers since they have the same molecular formula but different structures.
Explanation: Isomers are compounds having the same molecular formula but different structures. In the given straight$-$chain $4-C$ compounds$, Br$ is placed at different positions but the molecular formula is same.
In the given branched $4-C$ compounds, there is a branching of $-CH3$ at carbon $2$ but $Br$ is placed at positions $1$ and $2$ respectively.
So, all of these are isomers since they have the same molecular formula but different structures.
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