It is found that an increase in pressure of $100\, kPa$ causes a certain volume of water to decrease by $5 × 10^{-3}$ percent of its original volume. Then the speed of sound in the water is about .... $m/s$ (density of water $10^3 \,kg/m^3$)
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Bulk modulus $\beta=-\frac{\Delta \mathrm{P}}{\frac{\Delta \mathrm{v}}{\mathrm{v}}}=\frac{100 \times 10^{3}}{\frac{5 \times 10^{-3}}{100}}=2 \times 10^{9}$

speed $v=\sqrt{\frac{\beta}{\rho}}=\sqrt{\frac{2 \times 10^{9}}{10^{3}}} \approx 1414 \mathrm{\,m} / \mathrm{s}$

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