Question
It is given that at x = 1, the function ${x^4} - 62{x^2} + ax + 9$ attains its maximum value, on the interval [0, 2]. Find the value of a.
$\Rightarrow f'\left( x \right) = 4{x^3} - 124x + a$
Since, f(x) attains its maximum value at x = 1 in the interval [0, 2], therefore $f'\left( 1 \right) = 0$
$\therefore f'\left( 1 \right) = 4 - 124 + a = 0$
$\Rightarrow a - 120 = 0$
$\Rightarrow a = 120$
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