Question
It is given that at $x=1$, the function $x^4-62 x^2+a x+9$ attains its maximum value on the interval $[0,2]$. Find the value of $a$.

Answer

(b) : Let $f(x)=x^4-62 x^2+a x+9$.
Then, $f^{\prime}(x)=4 x^3-124 x+a$.
It is given that $f(x)$ attains its maximum at $x=1$
$
\therefore \quad f^{\prime}(1)=0 \Rightarrow 4-124+a=0 \Rightarrow a=120
$

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