Question
It is given that the functions $f(x) = 3x^2 - 1$ and $g(x) = 3 + x$ are equal.

Answer

$\therefore f(x)=g(x) \Rightarrow 3 x^2-1=3+x \Rightarrow 3 x^2-x-4=0 \Rightarrow(x+1)(3 x-4)=0 \Rightarrow x+1=0$ or $3 x-4=0 \Rightarrow x=-1$ or $x=\frac{4}{3}$

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