MCQ
It is given that $\triangle\text{ABC}\sim\text{PQR}$, with $\frac{\text{BC}}{\text{QR}}=\frac{1}{4}$ then, $\text{ar }\frac{\text{ar}\text({\triangle{\text{PRQ}}})}{\text{ar}\text({\text{ABC}})}$ is equal to :
  • $16$
  • B
    $4$
  • C
    $\frac{1}{4}$
  • D
    $\frac{1}{16}$

Answer

Correct option: A.
$16$
Given,
$\triangle\text{ABC}\sim\triangle\text{PQR}$
and$\frac{\text{BC}}{\text{QR}}=\frac{1}{4}$
Ratio of area of similar triangles is equal to the square of its corresponding sides.
So, $\frac{\text{ar}\text({\triangle{\text{PRQ}}})}{\text{ar}\text({\text{ABC}})}$
$=\Bigg(\frac{\text{QR}}{\text{BC}}\Bigg)^2=\Bigg(\frac{4}{1}\Bigg)^2=16$

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