MCQ
It is given that $\triangle\text{ABC}\sim\text{PQR}$, with $\frac{\text{BC}}{\text{QR}}=\frac{1}{4}$ then, $\text{ar }\frac{\text{ar}\text({\triangle{\text{PRQ}}})}{\text{ar}\text({\text{ABC}})}$ is equal to :
- ✓$16$
- B$4$
- C$\frac{1}{4}$
- D$\frac{1}{16}$

