MCQ
It is given that$\triangle\text{ABC}\cong\triangle\text{FDE}$ in which $AB = 5\ cm,$ $\angle\text{B}=40^{\circ},\angle\text{A}=80^{\circ}$and $FD = 5\ cm$. Then, which of the following is true?
  • A
    $\angle\text{D}=60^{\circ}$
  • $\angle\text{E}=60^{\circ}$
  • C
    $\angle\text{F}=60^{\circ}$
  • D
    $\angle\text{D}=80^{\circ}$

Answer

Correct option: B.
$\angle\text{E}=60^{\circ}$
Given $\triangle\text{ABC}\cong\triangle\text{FDE}$
$\angle\text{A}=\angle\text{F}=80^{\circ} ...(C.P.C.T.)$
$\angle\text{B}=\angle\text{D}=40^{\circ}...(C.P.C.T.)$
$\angle\text{A}+\angle\text{B}+\angle\text{C}=180^{\circ}$ ...(Angle sum property)
$\Rightarrow80^{\circ}+40^{\circ}+\angle\text{C}=180^{\circ}$
$\Rightarrow\angle\text{C}=60^{\circ}$
$\therefore\angle\text{E}=\angle\text{C}=60^{\circ}$
$\therefore\angle\text{E}=60^{\circ}$

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