$\xrightarrow{{{C}_{2}}{{H}_{5}}Cl}{{({{C}_{2}}{{H}_{5}})}_{3}}N\xrightarrow{{{C}_{2}}{{H}_{5}}Cl}$ $\underset{\text{Tetraethyl}\text{ammonium}\text{chloride}}{\mathop{{{\left[ \begin{matrix}
   \begin{matrix}
   \,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}}  \\
   |  \\
\end{matrix}  \\
   {{C}_{2}}{{H}_{5}}-N-{{C}_{2}}{{H}_{5}}  \\
   |  \\
   \,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}}  \\
\end{matrix} \right]}^{+}}}}\,C{{l}^{-}}$

 If $N{H_3}$ is in excess, then ${1^o}$ amine will be the main product, if ${C_2}{H_5}Cl$ is in excess then mixture of ${1^o},{2^o},{3^o}$ and quaternary amine is obtained.