- ACupramonium sulphate.
- BCopper sulphate tetraamonia.
- CTetrammine copper (II) sulphate.
- DCopper amonium (IV) sulphate.
Explanation:
Since 4 amino groups are present, it will be called as tetrammine.
Since copper(II) is the central metal, it will be tetrammine copper(II). Note that we can determine the oxidation number of copper by charge balance.
Now finally since sulphate is the counter ion, it's full name will be tetrammine copper(II) sulphate.
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(ii) Silver metal does not react with $1 M$ zinc nitrate solution
(iii) Zinc metal dissolves in $1M$ copper sulphate solution and copper metal gets depositedHence the order of decreasing strength of the three metals as reducing agents will be
Reason : The third ionization energy of $Mn$ is larger than that of $Cr$.
$Xe{{F}_{6}}\,\xrightarrow{+\,Excess\,\,{{H}_{2}}O}\,'X'\,+\,HF$
$Xe{{F}_{6}}\,\xrightarrow{+\,2\,\,{{H}_{2}}O}\,'Y'\,+\,HF$