Question
 IUPAC name of the given compound is:
$\text{H}_3\text{C}\text{−C​H}−\text{CH}_2\text{−C​H}\text{−C​H}​−\text{CH}_2−\text{CH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ | \\ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH} \ \ \ \ \ \ \ \ \ \ \ \ \ \text{OH} \ \ \ \ \text{C}_2\text{O}_5$

Answer

  1. 5-ethylheptane-2.4-diol
Explanation:
The compound have ethyl group at carbon no 5, two hydroxyl groups at carbon no 2 and 4. So its name is 5−ethylheptane−2.4−diol.

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