Question
जब $x + 2y = 8$, तब $xy $ का अधिकतम मान होगा
अब $f(x) = xy = x.\frac{{(8 - x)}}{2} = 4x - \frac{{{x^2}}}{2}$
$\therefore $ $f'(x) = 4 - x$
चरम बिन्दु के लिए, $f'(x) = 0$
$\therefore $ $x = 4$ व y = 2
अब $f''(x) = - 1 < 0$
अत: $xy$ का अधिकतम मान $ = 4 \times 2 = 8$.
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