MCQ
જો $a = i + j + k,\,\,a\,.\,b = 1$ અને $a \times b = j - k,$ તો $b = $
- ✓$i$
- B$i - j + k$
- C$2j - k$
- D$2i$
Now, $j - k = a \times b = \left| {\begin{array}{*{20}{c}}i&j&k\\1&1&1\\{{b_1}}&{{b_2}}&{{b_3}}\end{array}} \right|$
==> ${b_3} - {b_2} = 0,{b_1} - {b_3} = 1,{b_2} - {b_1} = - 1$
==> ${b_3} = {b_2},{b_1} = {b_2} + 1$
Now, $a.b = 1 \Rightarrow {b_1} + {b_2} + {b_3} = 1$
==> $3{b_2} + 1 = 1$$ \Rightarrow {b_2} = 0$==> ${b_1} = 1,{b_3} = 0$.
Thus $b = i$.
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