MCQ
જો બે અલગ ગણો $A$ અને $B$ હોય તો $n(A \cup B)$ =
- A$n(A)$
- B$n(B)$
- ✓$n(A) + n(B)$
- D$n(A)\,.\,n(B)$
$n(A \cap B) = 0$
Now $n\,(A \cup B) = n(A) + n(B) - n(A \cap B)$
$ = n(A) + n(B) - 0$$ = n(A) + n(B)$.
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