MCQ
જો $e^{x}+e^{y}=e^{x-y}$ તો $\frac{d y}{d x}=$  .....................

Answer

Correct option: C.
(C) $-e^{1-x}$
$\begin{array}{ll} & \\ & e^x+e^y=e^{x+y} \\ \therefore \quad & e^x+e^y=e^x \cdot e^y \\ \therefore & e^{-y}+e^{-x}=1\end{array}$
$\therefore \quad e^{-y}\left(-\frac{d y}{d x}\right)+e^{-x}(-1)=0$
$\begin{array}{l}\therefore \quad-e^{-y} \frac{d y}{d x}=e^{-x} \\ \therefore \quad \frac{d y}{d x}=-e^{y-r}\end{array}$

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