MCQ
જો $ f:R - \left\{0\right\}, f(x)=4x^3+3x^2+3x+4$ તો $x^3f \left(\frac{1}{x}\right)= $ ..........
- A$f(-x)$
- B$\frac{1}{f(x)}$
- C$\left(f\left(\frac{1}{x}\right)\right)^2$
- ✓$f(x)$
$f(x)$= $ 4x^3+3x^2+3x+4$
$\Rightarrow f\left(\frac{1}{x}\right) = \frac{4}{x^3} + \frac{3}{x^2} + \frac{3}{x} + 4 $
$\Rightarrow x^3f\left( \frac{1}{x} \right )$=$x^3 \left(\frac{4}{x^3}+\frac{3}{x^2}+\frac{3}{x}+4\right)$
$=4+3x+3x^2+4x^3=f(x)$
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