MCQ
જો $f(x) = \log \frac{{1 + x}}{{1 - x}}$, તો $f(x)$ એ . . . .
- Aયુગ્મ વિધેય
- B$f({x_1})f({x_2}) = f({x_1} + {x_2})$
- C$\frac{{f({x_1})}}{{f({x_2})}} = f({x_1} - {x_2})$
- ✓અયુગ્મ વિધેય
and $f( - x) = \log \left( {\frac{{1 - x}}{{1 + x}}} \right) = \log {\left( {\frac{{1 + x}}{{1 - x}}} \right)^{ - 1}}$
$ = - \log \left( {\frac{{1 + x}}{{1 - x}}} \right) = - f(x)$ ==> $f(x)$ is an odd function
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