મોલ \(\frac{{{\text{1}} \times {\text{1}}{{\text{0}}^{\text{3}}}}}{{58}}\,\,\,\,\,\,\,\,\,\frac{{13}}{2} \times \frac{{{{10}^3}}}{{58}}\)
\({W_{{O_2}}} = \frac{{13}}{2} \times \frac{{{{10}^3}}}{{58}} \times 32\,g\,\, = \,\,3.58\,\,kg\)
કારણ : $H_3PO_3$ નો તુલ્યભાર = $\frac{Molecular\, weight\, of\, H_3PO_3}{3}$