Similarly, $A ^{5}=\left(\begin{array}{cc}\cos 5 \theta & i \sin 5 \theta \\ i \sin 5 \theta & \cos 5 \theta\end{array}\right)=\left(\begin{array}{ll} a & b \\ c & d \end{array}\right)$
$a^{2}+b^{2}=\cos ^{2} 5 \theta-\sin ^{2} 5 \theta=\cos 10 \theta=\cos 75^{\circ}$
$a^{2}-d^{2}=\cos ^{2} 5 \theta-\cos ^{2} 5 \theta=0$
$a^{2}-b^{2}=\cos ^{2} 5 \theta+\sin ^{2} 5 \theta=1$
$a^{2}-c^{2}=\cos ^{2} 5 \theta+\sin ^{2} 5 \theta=1$
$\left(1+\cos ^{2} \theta\right) x+\sin ^{2} \theta y+4 \sin 3 \theta z=0$
$\cos ^{2} \theta x+\left(1+\sin ^{2} \theta\right) y+4 \sin 3 \theta z=0$
$\cos ^{2} \theta x+\sin ^{2} \theta y+(1+4 \sin 3 \theta) z=0$
ને શૂન્યતર ઉકેલ ધરાવે છે તો $\theta$ ની કિમંત મેળવો.