MCQ
જો $\sin A = \sin B$ અને $\cos A = \cos B,$ તો
- ✓$\sin \frac{{A - B}}{2} = 0$
- B$\sin \frac{{A + B}}{2} = 0$
- C$\cos \frac{{A - B}}{2} = 0$
- D$\cos (A + B) = 0$
$\frac{{\sin A}}{{\sin B}} = \frac{{\cos A}}{{\cos B}}\,$
$ \Rightarrow \,\,\sin A\,\cos B - \cos A\,\sin B = 0$
$ \Rightarrow \,\,\sin \,(A - B) = 0$
Hence, $\sin \,\left( {\frac{{A - B}}{2}} \right) = 0.$
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