MCQ
જો $\sin \left( {{{\sin }^{ - 1}}\frac{1}{5} + {{\cos }^{ - 1}}x} \right) = 1$,તો $ x = . . .$.
- A$1$
- B$0$
- C$\frac{4}{5}$
- ✓$\frac{1}{5}$
$\therefore \,\,{\sin ^{ - 1}}\frac{1}{5} = \frac{\pi }{2} - {\cos ^{ - 1}}x = {\sin ^{ - 1}}x$
$\therefore \,\,\,x = \frac{1}{5}$.
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