પરંતુ \(\mu \,\, = \,\,\,\frac{M}{{{M_w}}}\) અને \(\rho \,\, = \,\,\,\frac{M}{V} \) \(M\,\, = \,\,\rho V\,\,\,\,\,\therefore \,\,\,\mu \, = \,\,\frac{{\rho V}}{{{M_w}}}\)
સમીકરણ \((i)\) પરથી \(T\,\, = \,\,\,\frac{{PV{M_w}}}{{\rho VR}}\,\, = \,\,\frac{{P{M_w}}}{{\rho R}}\)
આપેલ :\( P = 1.4 \times 10^9 \,atmosphere = 1.4 \times 10^9 \times 1.01 \times 10^5 Nm^{-2}\)
\(\rho = 1.4 \,g\, cm^{-3} = 1.4 \times 1000 kg m^{-3},\, Mw = 2 \times 10^{-3} kg/mol\)
[વાયુ અચળાંક $8.3\, {J} {mol}^{-1} {K}^{-1}$ લો]