MCQ
જો $\tan A = 2\tan B + \cot B,$ તો $2\tan (A - B) = $
- A$\tan B$
- B$2\tan B$
- ✓$\cot B$
- D$2\cot B$
$ = 2\frac{{(2\tan B + \cot B - \tan B)}}{{1 + (2\,\tan B + \cot B)\,\tan B}} $
$= 2\,\frac{{\tan B + \cot B}}{{2\,(1 + {{\tan }^2}B)}}$
$ = \frac{{\cot B\,({{\tan }^2}B + 1)}}{{(1 + {{\tan }^2}B)}} $
$= \cot B$.
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