- A${\cos ^{ - 1}}\,\,\left( {\frac{7}{9}} \right)$
- B${\cos ^{ - 1}}\,\,\left( {\frac{7}{{11}}} \right)$
- C${\cos ^{ - 1}}\,\,\left( { - \frac{7}{{11}}} \right)$
- D${\cos ^{ - 1}}\,\,\left( {\frac{{6\sqrt 2 }}{{11}}} \right)$
$\vec a \,\, + \;\,2\vec b \,\, = \,\,i\,\, + \;\,j\,\, - \,\,k\, . . . .. (2)$ આપેલ છે
$(1)$ અને $(2)$ ને ઉકેલતા
$\vec a \,\, = \,\,\frac{1}{3}\,\,\left( {i\,\, + \;\,j\,\, + \,\,3k} \right)$ અને $\vec b \,\, = \,\,\frac{1}{3}\,\,\left( {i\,\, + \;\,j\,\, - \,\,3k} \right)$
તો $\cos \,\,\theta \,\, = \,\,\frac{{\vec a .\,\vec b \,}}{{|\vec a |\,.\,|\vec b |}}$
$\cos \,\,\theta \,\, = \,\,\frac{{\frac{1}{9}\,\,\left( {1\, + \,\,1\,\, - \,\,9} \right)}}{{\sqrt {\frac{1}{9}\,\,\left( {1\,\, + \;\,1\,\, + \;\,9} \right)\sqrt {\frac{1}{9}\,\,\left( {1\,\, + \;\,1\,\, + \;\,9} \right)} } }}\,\, $
$\Rightarrow \,\,\cos \,\,\theta \,\, = \,\,\frac{{\frac{1}{9}\,\,\left( { - 7} \right)}}{{\frac{1}{9}\,\,\sqrt {11} \,\,\sqrt {11} }}$
$\cos \,\,\theta \,\, = \,\,\frac{{ - 7}}{{11}}\,\, $
$\Rightarrow \,\,\theta \,\, = \,\,{\cos ^{ - 1}}\,\,\left( { - \frac{7}{{11}}} \right)$
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