જો $x = {2^{1/3}} - {2^{ - 1/3}},$ તો $2{x^3} + 6x = $
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c
(c) \(x = {2^{1/3}} - {2^{ - 1/3}}\)
(c) \(x = {2^{1/3}} - {2^{ - 1/3}}\)
\( \Rightarrow \)\({x^3} = 2 - {2^{ - 1}} - {3.2^{1/3}}{.2^{ - 1/3}}({2^{1/3}} - {2^{ - 1/3}})\)
\( \Rightarrow \)\({x^3} = 2 - {1 \over 2} - 3x\) ==> \({x^3} + 3x = {3 \over 2}\)
\(\therefore 2{x^3} + 6x = 3\).
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