MCQ
જો $x=f(t),y=g(t)$ તો $\frac{d^2y}{dx^2}=.....$
- A$\frac{f'g''-g'f''}{(f')^2}$
- ✓$\frac{f'g''-g'f''}{(f')^3}$
- C$\frac{f''}{g''}$
- D$\frac{g''}{f''}$
$\frac{dy}{dx}=\frac{g'(t)}{f'(t)}$
$\frac{d^2y}{dx^2}=\frac{d}{dx}\left(\frac{dy}{dx}\right)$
=$=\frac{d}{dt}\left(\frac{dy}{dx}\right).\frac{dt}{dx}=\frac{g''(t)f'(t)-g'(t)f''(t)}{[f'(t)]^2}\frac{1}{f'(t)}=\frac{f'g''-g't''}{(f')^3}$
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