MCQ
વિધેય $F(x) = \int_0^x {\log \left( {\frac{{1 - x}}{{1 + x}}} \right)} \,dx$ એ . . .
- ✓યુગ્મ વિધેય
- Bઅયુગ્મ વિધેય
- Cઆવર્તીય વિધેય
- Dએકપણ નહીં.
since the function here $f(x) = \log \frac{{1 - x}}{{1 + x}}$ is an odd function,
therefore $F(x)$ is an even function.
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અને $g(x) = (2x + 1)(x - k) + 3,\,0 \leqslant x < \infty $ આપેલ હોય તો $g(f(x))$ એ $x = 1$ આગળ સતત થાય જો $k= . . . $