MCQ
જો $y = 1 + x + {{{x^2}} \over {2!}} + {{{x^3}} \over {3!}} + .....\infty ,$ તો ${{dy} \over {dx}} = $
- ✓$y$
- B$y - 1$
- C$y + 1$
- Dએક પણ નહીં
Differentiating with respect to $x$ , we get $\frac{{dy}}{{dx}} = {e^x} = y$.
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