MCQ
જો $y = (1 + {x^{1/4}})(1 + {x^{1/2}})(1 - {x^{1/4}})$ , તો ${{dy} \over {dx}}=$
- A$1$
- ✓$-1$
- C$x$
- D$\sqrt x $
==> $y = (1 + {x^{1/4}})(1 - {x^{1/4}})(1 + {x^{1/2}})$
$\Rightarrow$ $(1 - {x^{1/2}})(1 + {x^{1/2}}) = 1 - x \Rightarrow \frac{{dy}}{{dx}} = - 1$.
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