MCQ
જો $y = {e^{x + {e^{x + {e^{x + ....\infty }}}}}}$, તો ${{dy} \over {dx}} = $
- ✓${y \over {1 - y}}$
- B${1 \over {1 - y}}$
- C${y \over {1 + y}}$
- D${y \over {y - 1}}$
==> $\frac{1}{y}\frac{{dy}}{{dx}} = 1 + \frac{{dy}}{{dx}}$
==> $ \frac{{dy}}{{dx}} = \frac{y}{1-y} $.
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$\left(1+\cos ^{2} \theta\right) x+\sin ^{2} \theta y+4 \sin 3 \theta z=0$
$\cos ^{2} \theta x+\left(1+\sin ^{2} \theta\right) y+4 \sin 3 \theta z=0$
$\cos ^{2} \theta x+\sin ^{2} \theta y+(1+4 \sin 3 \theta) z=0$
ને શૂન્યતર ઉકેલ ધરાવે છે તો $\theta$ ની કિમંત મેળવો.