MCQ
જો $\mathrm{y}(\alpha)=\sqrt{2\left(\frac{\tan \alpha+\cot \alpha}{1+\tan ^{2} \alpha}\right)+\frac{1}{\sin ^{2} \alpha}}, \alpha \in\left(\frac{3 \pi}{4}, \pi\right)$ તો $\frac{d y}{d \alpha}$ એ $\alpha=\frac{5 \pi}{6}$ આગળ કિમત મેળવો.
- ✓$4$
- B$-\frac{1}{4}$
- C$\frac{4}{3}$
- D$-4$