$H_2S$ does not evolve as liberated $H_2S$ is neutralized by $NaOH$ and $Na_2S$ is formed.
$2X_2 (g) + 2H_2O (l) \to 4H^+ (aq) + 4X^-(aq) + O_2 (g)$
$Y_2 (g) + H_2O (l) \to HY(aq) + HOY(aq)$
$ClF _{3}, IF _{7}, BrF _{5^{2}}, BrF _{3}, I _{2} Cl _{6^{\prime}} IF _{5}, ClF , ClF _{5}$